(2x-5)^2/3=-8

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Solution for (2x-5)^2/3=-8 equation: 


x in (-oo:+oo)

((2*x-5)^2)/3 = -8 // + 8

((2*x-5)^2)/3+8 = 0

((2*x-5)^2)/3+(3*8)/3 = 0

(2*x-5)^2+3*8 = 0

4*x^2-20*x+49 = 0

4*x^2-20*x+49 = 0

4*x^2-20*x+49 = 0

DELTA = (-20)^2-(4*4*49)

DELTA = -384

DELTA < 0

1 = 0

1/3 = 0

1/3 = 0 // * 3

1 = 0

x belongs to the empty set

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